What is the domain of \sqrt[6]{x^2-8x-9} ?

The domain of \sqrt[6]{x^2-8x-9} is x = 9

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domain of \sqrt[6]{x^2-8x-9}

domain

x \leq - 1 or x \geq 9

Interval Notation

(- \infty, - 1] \cup [9, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 9

The function domain

x \leq - 1 or x \geq 9

f (x) = \frac{x ^{2} - 1}{x ^{2} + 2 x - 3}

x = - 19, (6, 1)

f (x) = 8 + \frac{4}{x}

y = m x + b

(0, - 7), (- 6, - 2)

What is the domain of \sqrt[6]{x^2-8x-9} ?
The domain of \sqrt[6]{x^2-8x-9} is x<=-1\lor x>= 9