What is the critical f(x)=(x^2-2x+4)/(x-2) ?

The critical f(x)=(x^2-2x+4)/(x-2) is x=0,x=4

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critical f(x)=(x^2-2x+4)/(x-2)

critical points

f (x) = \frac{x ^{2} - 2 x + 4}{x - 2}

x = 0, x = 4

Solution steps

\frac{x ^{2} - 2 x + 4}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2 x + 4}{x - 2} : x < 2 or x > 2

\frac{x ^{2} - 2 x + 4}{x - 2}

is not defined at

x = 2

, therefore:

x = 0, x = 4

x + 2 y = 10

f (x) = - 4 x^{2} + 2 x + 2

y = 2 x + 4

\frac{8 + 7 x}{6 x - 7}

(3, 6), (1, - 2)

What is the critical f(x)=(x^2-2x+4)/(x-2) ?
The critical f(x)=(x^2-2x+4)/(x-2) is x=0,x=4