What is the domain of r(t)=(2t^2}{1-t^2}\frac{t+1)/t ?

The domain of r(t)=(2t^2}{1-t^2}\frac{t+1)/t is r 0

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domain of r(t)=(2t^2}{1-t^2}\frac{t+1)/t

domain

r (t) = \frac{2 t ^{2}}{1 - t ^{2}} \frac{t + 1}{t}

r < 0 or r > 0

Solution steps

Find undefined (singularity) points:

r = 0

The function domain

r < 0 or r > 0

6 x - 4 y = 12

f (x) = x^{5} tan (x)

x^{2} - 10 x + 16

z

f (x) = x^{2} + 9, x \geq - 5

What is the domain of r(t)=(2t^2}{1-t^2}\frac{t+1)/t ?
The domain of r(t)=(2t^2}{1-t^2}\frac{t+1)/t is r<0\lor r>0