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Popular >

extreme f(x)= 1/(x^2+1)

Solution

extreme points

f (x) = \frac{1}{x ^{2} + 1}

Solution

Maximum (0, 1)

Solution steps

f^{'} (x) = - \frac{2 x}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{1}{x ^{2} + 1} : 1

Maximum (0, 1)

Popular Examples

inflection x^4-2x^2+1 inflection points

x^{4} - 2 x^{2} + 1

range of 1/(sqrt(t))range

\frac{1}{t}

inverse of-x^3-2 inverse

- x^{3} - 2

extreme f(x)=x^2+4x+3 extreme points

f (x) = x^{2} + 4 x + 3

slope ofintercept f(x)=-0.388x+170.96 slope intercept

f (x) = - 0.388 x + 170.96

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 1/(x^2+1) ?
The extreme f(x)= 1/(x^2+1) is Maximum(0,1)