What is the inverse of f(x)=16+\sqrt[3]{x} ?

The inverse of f(x)=16+\sqrt[3]{x} is x^3-48x^2+768x-4096

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inverse of f(x)=16+\sqrt[3]{x}

inverse

x^{3} - 48 x^{2} + 768 x - 4096

Solution steps

Replace

x

with

y

Solve for

x^{3} - 48 x^{2} + 768 x - 4096

f (x) = \frac{1}{5} (x + 18)^{3} - 4

\frac{x + 5}{x ^{2} - 16}

\frac{x ^{2} + 3}{2}

y = x (x - 4)

f (x) = \frac{1}{x ^{2} + 3 x - 10}

What is the inverse of f(x)=16+\sqrt[3]{x} ?
The inverse of f(x)=16+\sqrt[3]{x} is x^3-48x^2+768x-4096