What is the inverse of f(x)=log_{5}((1-x)/(1+x)) ?

The inverse of f(x)=log_{5}((1-x)/(1+x)) is (1-5^x)/(5^x+1)

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inverse of f(x)=log_{5}((1-x)/(1+x))

inverse

f (x) = lo g_{5} (\frac{1 - x}{1 + x})

\frac{1 - 5 ^{x}}{5 ^{x} + 1}

Solution steps

y = lo g_{5} (\frac{1 - x}{1 + x})

Replace

x

with

y

x = lo g_{5} (\frac{1 - y}{1 + y})

Solve for

y, x = lo g_{5} (\frac{1 - y}{1 + y})

\frac{1 - 5 ^{x}}{5 ^{x} + 1}

f (x) = (x) - 5

- 3 x^{2} - 2 x + 5

f (s) = 1 + \frac{( c + 16 s )}{c + s} \cdot \frac{9}{s ^{2}}

\frac{5 x}{2 x + 3}

f (x) = x^{2} + 2 x + 5

What is the inverse of f(x)=log_{5}((1-x)/(1+x)) ?
The inverse of f(x)=log_{5}((1-x)/(1+x)) is (1-5^x)/(5^x+1)