What is the domain of f(x)=sqrt((x-2)(x-3)(x-4)) ?

The domain of f(x)=sqrt((x-2)(x-3)(x-4)) is 2 = 4

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domain of f(x)=sqrt((x-2)(x-3)(x-4))

domain

f (x) = (x - 2) (x - 3) (x - 4)

2 \leq x \leq 3 or x \geq 4

Interval Notation

[2, 3] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

2 \leq x \leq 3 or x \geq 4

The function domain

2 \leq x \leq 3 or x \geq 4

(- 23, 3), (- 25, - 10)

f (x) = \frac{x + 5}{x ^{2} - 49}

f (x) = - 3 + \frac{7}{3} x

f (x) = (x - 2)^{2} + 4

f (x) = x - \frac{128}{x}

What is the domain of f(x)=sqrt((x-2)(x-3)(x-4)) ?
The domain of f(x)=sqrt((x-2)(x-3)(x-4)) is 2<= x<= 3\lor x>= 4