What is the shift 4csc((5pi)/3 x-(20pi)/3) ?

The shift 4csc((5pi)/3 x-(20pi)/3) is Phase:4, Vertical:0

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shift 4csc((5pi)/3 x-(20pi)/3)

shift

4 csc (\frac{5 π}{3} x - \frac{20 π}{3})

Phase : 4, Vertical : 0

Solution steps

Simplify

4 csc (\frac{5 π}{3} x - \frac{20 π}{3}) : 4 csc (\frac{5 π x - 20 π}{3})

f (x) = 4 csc (\frac{5 π x - 20 π}{3})

g (B x - C) = csc (\frac{5 π x - 20 π}{3}), B = - 5 π + \frac{20 π}{3}, C = \frac{20 π}{3}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{20 π}{3}}{- 5 π + \frac{20 π}{3}}

4

The vertical shift

D

0

0

f (x) = x^{2} + 3 \cdot x + 2

f (x) = x^{2} - 10

f (x) = \frac{8}{3 x + 1}

20 x - 4

What is the shift 4csc((5pi)/3 x-(20pi)/3) ?
The shift 4csc((5pi)/3 x-(20pi)/3) is Phase:4, Vertical:0