What is the perpendicular y=-7/4 x-1/2 ,(11,13) ?

The perpendicular y=-7/4 x-1/2 ,(11,13) is y= 4/7 x+47/7

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perpendicular y=-7/4 x-1/2 ,(11,13)

perpendicular

y = - \frac{7}{4} x - \frac{1}{2}, (11, 13)

y = \frac{4}{7} x + \frac{47}{7}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{7}{4} x - \frac{1}{2}

that passes through

(11, 13)

Find the slope of

y = - \frac{7}{4} x - \frac{1}{2} : m = - \frac{7}{4}

Compute the slope of the perpendicular line:

m_{p} = \frac{4}{7}

Find the line with slope m=

\frac{4}{7}

and passing through

(11, 13) : y = \frac{4}{7} x + \frac{47}{7}

y = \frac{4}{7} x + \frac{47}{7}

f (x) = \frac{( x ^{2} - 25 )}{( x + 5 )}

f (x) = 3 x^{\frac{1}{2}}

f (x) = x^{2} - 8

f (x) = \frac{2}{1 - x}

f (x) = \frac{( 4 x ^{3} )}{x - 5}

What is the perpendicular y=-7/4 x-1/2 ,(11,13) ?
The perpendicular y=-7/4 x-1/2 ,(11,13) is y= 4/7 x+47/7