What is the extreme f(x)=x^3-75x+3 ?

The extreme f(x)=x^3-75x+3 is Maximum(-5,253),Minimum(5,-247)

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extreme f(x)=x^3-75x+3

extreme points

f (x) = x^{3} - 75 x + 3

Maximum (- 5, 253), Minimum (5, - 247)

Solution steps

f^{'} (x) = 3 x^{2} - 75

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{3} - 75 x + 3 : 253

Maximum (- 5, 253)

Plug

x = 5

into

x^{3} - 75 x + 3 : - 247

Minimum (5, - 247)

Maximum (- 5, 253), Minimum (5, - 247)

f (x) = \frac{( x ^{2} - 4 x + 3 )}{x - 1}

y + 4 = (- \frac{7}{8}) (x - 7)

2 x^{2} + x - 8

f (x) = \frac{6}{x}

(0, - 2), (- 5, 3)

What is the extreme f(x)=x^3-75x+3 ?
The extreme f(x)=x^3-75x+3 is Maximum(-5,253),Minimum(5,-247)