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midpoint
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global f(x)=x^3-3x+8global extreme points parallel 5x+6y=7,(5,-2)parallel inverse of f(x)=(7x)/(x+2)inverse critical x^3+3(27-3x^2)^2+7critical points midpoint (2,3),(-5,-7)midpoint
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-4),(-7,-5) ?
The midpoint (-2,-4),(-7,-5) is (-9/2 ,-9/2)