What is the inverse of f(x)=x^2-6,x>= 0 ?

The inverse of f(x)=x^2-6,x>= 0 is sqrt(x+6),-sqrt(x+6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2-6,x>= 0

inverse

f (x) = x^{2} - 6, x \geq 0

x + 6, - x + 6

Solution steps

y = x^{2} - 6

Replace

x

with

y

x = y^{2} - 6

Solve for

y, x = y^{2} - 6

x + 6, - x + 6

(0.6) (0)

(2, - 2), (- 1, 4)

f (x) = \frac{( x - 2 )}{( 4 x + 6 )}

\frac{s}{s ^{2} + 4 s + 5}

f (x) = \frac{x}{x ^{2} - x + 1}

What is the inverse of f(x)=x^2-6,x>= 0 ?
The inverse of f(x)=x^2-6,x>= 0 is sqrt(x+6),-sqrt(x+6)