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Popular >

range of f(x)=-2x^2-2x+2

Solution

range

f (x) = - 2 x^{2} - 2 x + 2

Solution

f (x) \leq \frac{5}{2}

+1

Interval Notation

(- \infty, \frac{5}{2}]

Solution steps

Vertex of

- 2 x^{2} - 2 x + 2 :

Maximum

(- \frac{1}{2}, \frac{5}{2})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 2,

Vertex

(x_{v}, y_{v}) = (- \frac{1}{2}, \frac{5}{2})

f (x) \leq \frac{5}{2}

Popular Examples

intercepts of f(x)=2x+3y=6 intercepts

f (x) = 2 x + 3 y = 6

inverse of f(x)=\sqrt[3]{x-4}inverse

domain of (32)/y-(y+1)/(y+7)domain

\frac{32}{y} - \frac{y + 1}{y + 7}

domain of (x-3)/(x-4)domain

\frac{x - 3}{x - 4}

range of x^2-4x range

x^{2} - 4 x

Frequently Asked Questions (FAQ)

What is the range of f(x)=-2x^2-2x+2 ?
The range of f(x)=-2x^2-2x+2 is f(x)<= 5/2