What is the inverse of f(x)= 1/3 (x-2.1)^2+7.9 ?

The inverse of f(x)= 1/3 (x-2.1)^2+7.9 is sqrt(3x-23.7)+2.1,-sqrt(3x-23.7)+2.1

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inverse of f(x)= 1/3 (x-2.1)^2+7.9

inverse

f (x) = \frac{1}{3} (x - 2.1)^{2} + 7.9

3 x - 23.7 + 2.1, - 3 x - 23.7 + 2.1

Solution steps

y = \frac{1}{3} (x - 2.1)^{2} + 7.9

Replace

x

with

y

x = \frac{1}{3} (y - 2.1)^{2} + 7.9

Solve for

y, x = \frac{1}{3} (y - 2.1)^{2} + 7.9

3 x - 23.7 + 2.1, - 3 x - 23.7 + 2.1

y = - \frac{x}{4} + 5

f (x) = (x + 8)^{2}

- 6 cos (- 4 x - \frac{π}{8})

f (x) = (2 x + 1) e^{3 x}

2 x^{2} - 5

What is the inverse of f(x)= 1/3 (x-2.1)^2+7.9 ?
The inverse of f(x)= 1/3 (x-2.1)^2+7.9 is sqrt(3x-23.7)+2.1,-sqrt(3x-23.7)+2.1