What is the critical ((x^3-x))/(1+x^2) ?

The critical ((x^3-x))/(1+x^2) is x=-sqrt(-2+\sqrt{5)},x=sqrt(-2+\sqrt{5)}

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critical ((x^3-x))/(1+x^2)

critical points

\frac{( x ^{3} - x )}{1 + x ^{2}}

x = - - 2 + 5, x = - 2 + 5

Solution steps

\frac{x ^{3} - x}{1 + x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - - 2 + 5, x = - 2 + 5

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3} - x}{1 + x ^{2}} : - \infty < x < \infty

All critical points are in domain

x = - - 2 + 5, x = - 2 + 5

f (x) = \frac{6 x - 12 x ^{9}}{3 x ^{3} + 7}

f (x) = \frac{( 2 x - 1 )}{x + 3}

h (x) = x - 10

f (x) = \frac{2}{4 x - 3}

f (x) = \frac{4 x}{2 x + 3}

What is the critical ((x^3-x))/(1+x^2) ?
The critical ((x^3-x))/(1+x^2) is x=-sqrt(-2+\sqrt{5)},x=sqrt(-2+\sqrt{5)}