What is the inverse of sqrt(4-x^2) ?

The inverse of sqrt(4-x^2) is sqrt(-x^2+4),-sqrt(-x^2+4)

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inverse of sqrt(4-x^2)

inverse

4 - x^{2}

- x^{2} + 4, - - x^{2} + 4

Solution steps

y = 4 - x^{2}

Replace

x

with

y

x = 4 - y^{2}

Solve for

y, x = 4 - y^{2}

- x^{2} + 4, - - x^{2} + 4

\frac{1}{x + 13}

- 3 x - 4 y = - 4

f (x) = 2 sin (\frac{1}{2} x)

f (x) = x - sin (x)

f (x) = 4 - 7 x

What is the inverse of sqrt(4-x^2) ?
The inverse of sqrt(4-x^2) is sqrt(-x^2+4),-sqrt(-x^2+4)