What is the critical r^2+8.12r+3364 ?

The critical r^2+8.12r+3364 is r=-4.06

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critical r^2+8.12r+3364

critical points

r^{2} + 8.12 r + 3364

r = - 4.06

Solution steps

r^{2} + 8.12 r + 3364

Find where

f^{'} (r)

is equal to zero or undefined

r = - 4.06

Identify critical points not in

f (r)

domain

Domain of

r^{2} + 8.12 r + 3364 : - \infty < r < \infty

All critical points are in domain

r = - 4.06

y = - x^{2} + 2 x - 4

(2) (8.8)

f (x) = \frac{2 x ^{2} - x - 3}{x ^{2} + 1}

3 x + y = 6

2 x^{3} + 4