What is the domain of f(x)=sqrt(x-1)+2 ?

The domain of f(x)=sqrt(x-1)+2 is x>= 1

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domain of f(x)=sqrt(x-1)+2

domain

f (x) = x - 1 + 2

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

y = - \frac{3}{2} x - 5

f (x) = \frac{1}{x - 3}

f (x) = 12 x - 9

f (x) = lo g_{2} (x - 3) - 1

\frac{1}{x ^{4} - 37 x ^{2} + 36}

What is the domain of f(x)=sqrt(x-1)+2 ?
The domain of f(x)=sqrt(x-1)+2 is x>= 1