What is the perpendicular 3x+5y=15,(3,2) ?

The perpendicular 3x+5y=15,(3,2) is y= 5/3 x-3

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perpendicular 3x+5y=15,(3,2)

perpendicular

3 x + 5 y = 15, (3, 2)

y = \frac{5}{3} x - 3

Solution steps

Find the line

y = mx + b

perpendicular to

3 x + 5 y = 15

that passes through

(3, 2)

Find the slope of

3 x + 5 y = 15 : m = - \frac{3}{5}

Compute the slope of the perpendicular line:

m_{p} = \frac{5}{3}

Find the line with slope m=

\frac{5}{3}

and passing through

(3, 2) : y = \frac{5}{3} x - 3

y = \frac{5}{3} x - 3

- 1.5

f (x) = (5 x + 1)^{3}

f (x) = \frac{1}{10} x^{5} - 5 x^{3}

y = \frac{49}{x ^{2}}

x^{2} - 2 x - 15

What is the perpendicular 3x+5y=15,(3,2) ?
The perpendicular 3x+5y=15,(3,2) is y= 5/3 x-3