What is the range of (8x+9)/(x+8) ?

The range of (8x+9)/(x+8) is f(x) 8

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range of (8x+9)/(x+8)

range

\frac{8 x + 9}{x + 8}

f (x) < 8 or f (x) > 8

Interval Notation

(- \infty, 8) \cup (8, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{8 x + 9}{x + 8}

Inverse of

\frac{8 x + 9}{x + 8} : \frac{9 - 8 x}{x - 8}

\frac{9 - 8 x}{x - 8}

Find the domain of each inverse function

Domain of

\frac{9 - 8 x}{x - 8} : x < 8 or x > 8

Combine the intervals

f (x) < 8 or f (x) > 8

\frac{1}{4} x^{4} - \frac{1}{3} x^{3} - 3 x^{2}

\frac{2 x}{x ^{2} - 1}

\frac{1}{1 - x + 1}

f (x) = 2 - 4 x

f (x) = \frac{x}{4}

What is the range of (8x+9)/(x+8) ?
The range of (8x+9)/(x+8) is f(x)<8\lor f(x)>8