What is the domain of f(x)= 1/(1-\frac{1){(x-2)}} ?

The domain of f(x)= 1/(1-\frac{1){(x-2)}} is x 3

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domain of f(x)= 1/(1-\frac{1){(x-2)}}

domain

f (x) = \frac{1}{1 - \frac{1}{( x - 2 )}}

x < 2 or 2 < x < 3 or x > 3

Interval Notation

(- \infty, 2) \cup (2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 2

The function domain

x < 2 or 2 < x < 3 or x > 3

(- 3, 2), (- 3, - 2)

f (x) = \frac{1}{x ^{2} ( x + 9 )}

\frac{( x + 2 ) ^{2}}{x - 1}

f (x) = 2 x + 3 y - 5 = 0

f (x) = \frac{3 x}{x - 3}

What is the domain of f(x)= 1/(1-\frac{1){(x-2)}} ?
The domain of f(x)= 1/(1-\frac{1){(x-2)}} is x<2\lor 2<x<3\lor x>3