What is the asymptotes of f(x)=(t^2)/(t^2-9) ?

The asymptotes of f(x)=(t^2)/(t^2-9) is Vertical: t=-3,t=3,Horizontal: x=1

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asymptotes of f(x)=(t^2)/(t^2-9)

asymptotes

f (x) = \frac{t ^{2}}{t ^{2} - 9}

Vertical : t = - 3, t = 3, Horizontal : x = 1

Solution steps

Vertical asymptotes of

\frac{t ^{2}}{t ^{2} - 9} : t = - 3, t = 3

Horizontal Asymptotes of

\frac{t ^{2}}{t ^{2} - 9} : x = 1

Slant Asymptotes of

\frac{t ^{2}}{t ^{2} - 9} :

None

Vertical : t = - 3, t = 3, Horizontal : x = 1

f (x) = 2 x^{2} - 4 x - 7

f (x) = x^{2} - 5 x + 1

x^{2} - 6

F (x) = (x + 4) (x - 1)^{2}

f (x) = \frac{2 x}{3 x ^{2} - 12}

What is the asymptotes of f(x)=(t^2)/(t^2-9) ?
The asymptotes of f(x)=(t^2)/(t^2-9) is Vertical: t=-3,t=3,Horizontal: x=1