What is the critical f(x)=sqrt(x^2+1) ?

The critical f(x)=sqrt(x^2+1) is x=0

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critical f(x)=sqrt(x^2+1)

critical points

f (x) = x^{2} + 1

x = 0

Solution steps

x^{2} + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} + 1 : - \infty < x < \infty

All critical points are in domain

x = 0

\frac{x ^{2} + 8 x - 9}{x ^{2} + 3 x - 4}

f (x) = \frac{( x + 4 )}{( x ^{2} - 9 )}

(1, 2), (- 3, 5)

\frac{x}{x + 9}

f (x) = \frac{x + 3}{x - 8}