What is the domain of f(x)=\sqrt[266]{1.25x-3/7} ?

The domain of f(x)=\sqrt[266]{1.25x-3/7} is x>= 12/35

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domain of f(x)=\sqrt[266]{1.25x-3/7}

domain

x \geq \frac{12}{35}

Interval Notation

[\frac{12}{35}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{12}{35}

The function domain

x \geq \frac{12}{35}

f (x) = \frac{x - 7}{x + 6}

y = 3 x + 1, (6, 9)

f (x) = (x^{2} - 1)^{\frac{1}{5}}

f (x) = 7 - x

f (x) = arccos (\frac{x}{2})

What is the domain of f(x)=\sqrt[266]{1.25x-3/7} ?
The domain of f(x)=\sqrt[266]{1.25x-3/7} is x>= 12/35