What is the domain of f(x)= 5/(sqrt(x-2)) ?

The domain of f(x)= 5/(sqrt(x-2)) is x>2

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domain of f(x)= 5/(sqrt(x-2))

domain

f (x) = \frac{5}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

\frac{x}{x ^{2} - 6 x + 8}

f (x) = \frac{9 x ( x - 7 )}{2 x ^{2} - 5 x - 3}

f (x) = x^{3} - 3 x^{2} - 3 x + 5

f (x) = - \frac{3}{x - 1} - 2

f (x) = 3 - (x + 12.2)^{2} - 3

What is the domain of f(x)= 5/(sqrt(x-2)) ?
The domain of f(x)= 5/(sqrt(x-2)) is x>2