What is the extreme f(x)=-8x^3+24x+7 ?

The extreme f(x)=-8x^3+24x+7 is Minimum(-1,-9),Maximum(1,23)

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extreme f(x)=-8x^3+24x+7

extreme points

f (x) = - 8 x^{3} + 24 x + 7

Minimum (- 1, - 9), Maximum (1, 23)

Solution steps

f^{'} (x) = - 24 x^{2} + 24

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- 8 x^{3} + 24 x + 7 : - 9

Minimum (- 1, - 9)

Plug

x = 1

into

- 8 x^{3} + 24 x + 7 : 23

Maximum (1, 23)

Minimum (- 1, - 9), Maximum (1, 23)

f (x) = x^{2} + 8 x

f (x) = 5 (x + 4)^{2} - 1

y = 7 - 4 x

f (x) = \frac{x ^{2} - 2 x - 3}{x + 1}

f (x) = 4 2 x - 3

What is the extreme f(x)=-8x^3+24x+7 ?
The extreme f(x)=-8x^3+24x+7 is Minimum(-1,-9),Maximum(1,23)