What is the domain of f(x)=sqrt(t^2+1) ?

The domain of f(x)=sqrt(t^2+1) is -infinity <t<infinity

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domain of f(x)=sqrt(t^2+1)

domain

f (x) = t^{2} + 1

- \infty < t < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < t < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

f (x) = 2 x^{2} - 32

f (x) = x^{3} - 4 x^{2} - 4 x + 16

f (x) = 3 x^{2} - 16 x + 5

f (x) = \frac{1}{( x + 1 ) ^{2}}

What is the domain of f(x)=sqrt(t^2+1) ?
The domain of f(x)=sqrt(t^2+1) is -infinity <t<infinity