What is the critical ((4x+9))/(6x+3) ?

The critical ((4x+9))/(6x+3) is None

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critical ((4x+9))/(6x+3)

critical points

\frac{( 4 x + 9 )}{6 x + 3}

None

Solution steps

\frac{4 x + 9}{6 x + 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{4 x + 9}{6 x + 3} : x < - \frac{1}{2} or x > - \frac{1}{2}

\frac{4 x + 9}{6 x + 3}

is not defined at

x = - \frac{1}{2}

, therefore:

None

f (x) = 1 + 3 + 4 x

x + 2 y = 16

m = 2, (7, - 9)

x e^{x}

f (t) = 10 e^{0.1 t}