What is the line (4, 3/2),(7, 3/5) ?

The line (4, 3/2),(7, 3/5) is y=-3/10 x+27/10

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line (4, 3/2),(7, 3/5)

line

(4, \frac{3}{2}), (7, \frac{3}{5})

y = - \frac{3}{10} x + \frac{27}{10}

Solution steps

Find the line

y = mx + b

passing through

(4, \frac{3}{2})

(7, \frac{3}{5})

Compute the slope

(4, \frac{3}{2}), (7, \frac{3}{5}) : m = - \frac{3}{10}

Compute the

y

intercept:

b = \frac{27}{10}

Construct the line equation

y = mx + b

where

m = - \frac{3}{10}

and

b = \frac{27}{10}

y = - \frac{3}{10} x + \frac{27}{10}

f (x) = tan (\frac{π}{2} x)

(7, - 1), (3, 8)

y + x = 5

f (x) = \frac{5}{x + 1}

(- \frac{1}{3}, 2), (\frac{5}{3}, - \frac{2}{3})

What is the line (4, 3/2),(7, 3/5) ?
The line (4, 3/2),(7, 3/5) is y=-3/10 x+27/10