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Popular >

distance (-1/3 ,2),(5/3 ,-2/3)

Solution

distance

(- \frac{1}{3}, 2), (\frac{5}{3}, - \frac{2}{3})

Solution

\frac{10}{3}

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- \frac{1}{3}, 2)

and

(\frac{5}{3}, - \frac{2}{3})

is

= (\frac{5}{3} - (- \frac{1}{3}))^{2} + (- \frac{2}{3} - 2)^{2}

Simplify

= \frac{10}{3}

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f (x) = \frac{( x - 1 ) ^{2}}{x + 1}

inverse of f(x)=2.5n+17 inverse

f (x) = 2.5 n + 17

inverse of f(x)=\sqrt[3]{x}+5 inverse

inverse of f(x)=(2x-4)/(x+3)inverse

f (x) = \frac{2 x - 4}{x + 3}

asymptotes of f(x)=(1-sqrt(x))/(sqrt(x))asymptotes

f (x) = \frac{1 - x}{x}

Frequently Asked Questions (FAQ)

What is the distance (-1/3 ,2),(5/3 ,-2/3) ?
The distance (-1/3 ,2),(5/3 ,-2/3) is 10/3