What is the inverse of f(x)=\sqrt[3]{x}+5 ?

The inverse of f(x)=\sqrt[3]{x}+5 is x^3-15x^2+75x-125

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inverse of f(x)=\sqrt[3]{x}+5

inverse

x^{3} - 15 x^{2} + 75 x - 125

Solution steps

Replace

x

with

y

Solve for

x^{3} - 15 x^{2} + 75 x - 125

f (x) = \frac{2 x - 4}{x + 3}

f (x) = \frac{1 - x}{x}

f (x) = x^{2} - 4 x - 3

f (x) = 1 + x

y = \frac{( 2 x + 2 )}{3 x + 1}

What is the inverse of f(x)=\sqrt[3]{x}+5 ?
The inverse of f(x)=\sqrt[3]{x}+5 is x^3-15x^2+75x-125