What is the asymptotes of y=((2x+2))/(3x+1) ?

The asymptotes of y=((2x+2))/(3x+1) is Vertical: x=-1/3 ,Horizontal: y= 2/3

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asymptotes of y=((2x+2))/(3x+1)

asymptotes

y = \frac{( 2 x + 2 )}{3 x + 1}

Vertical : x = - \frac{1}{3}, Horizontal : y = \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{2 x + 2}{3 x + 1} : x = - \frac{1}{3}

Horizontal Asymptotes of

\frac{2 x + 2}{3 x + 1} : y = \frac{2}{3}

Slant Asymptotes of

\frac{2 x + 2}{3 x + 1} :

None

Vertical : x = - \frac{1}{3}, Horizontal : y = \frac{2}{3}

f (x) = x^{3} + x^{2} - 5 x - 2

f (x) = \frac{3}{4 x} - 5

f (x) = 2 - x^{2}, - 4 \leq x \leq 4

f (x) = - \frac{1}{4}

f (x) = \frac{8 x}{9 x - 1}

What is the asymptotes of y=((2x+2))/(3x+1) ?
The asymptotes of y=((2x+2))/(3x+1) is Vertical: x=-1/3 ,Horizontal: y= 2/3