What is the extreme f(x)=x^3-12x+13 ?

The extreme f(x)=x^3-12x+13 is Maximum(-2,29),Minimum(2,-3)

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extreme f(x)=x^3-12x+13

extreme points

f (x) = x^{3} - 12 x + 13

Maximum (- 2, 29), Minimum (2, - 3)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x + 13 : 29

Maximum (- 2, 29)

Plug

x = 2

into

x^{3} - 12 x + 13 : - 3

Minimum (2, - 3)

Maximum (- 2, 29), Minimum (2, - 3)

f (x) = \frac{2 x}{x - 2}

s^{3}

f (x) = - 3 - \frac{4}{5} x

y = \frac{x ^{2} + 7 x - 1}{x - 1}

12 x + 1

What is the extreme f(x)=x^3-12x+13 ?
The extreme f(x)=x^3-12x+13 is Maximum(-2,29),Minimum(2,-3)