What is the extreme f(x)=4x^3-48x-5 ?

The extreme f(x)=4x^3-48x-5 is Maximum(-2,59),Minimum(2,-69)

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extreme f(x)=4x^3-48x-5

extreme points

f (x) = 4 x^{3} - 48 x - 5

Maximum (- 2, 59), Minimum (2, - 69)

Solution steps

f^{'} (x) = 12 x^{2} - 48

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

4 x^{3} - 48 x - 5 : 59

Maximum (- 2, 59)

Plug

x = 2

into

4 x^{3} - 48 x - 5 : - 69

Minimum (2, - 69)

Maximum (- 2, 59), Minimum (2, - 69)

f (x) = x^{3} + 2 x^{2} - x + 4

f (x) = \frac{1}{x x ^{2} + 2}

∣ x - 2 ∣

f (x) = x^{3} + 5

y = 5 cos (2 x + \frac{π}{2})

What is the extreme f(x)=4x^3-48x-5 ?
The extreme f(x)=4x^3-48x-5 is Maximum(-2,59),Minimum(2,-69)