What is the domain of f(x)=sqrt(2+x+x^2) ?

The domain of f(x)=sqrt(2+x+x^2) is -infinity <x<infinity

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domain of f(x)=sqrt(2+x+x^2)

domain

f (x) = 2 + x + x^{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

(22, 38), (3, 9)

f (x) = \frac{x ^{2} - 9}{x + 1}

f (x) = x - 5

f (x) = t^{4} - 8 t^{3} + 10 t^{2}

x - 5 y - 3 = 0, (8, - 7)

What is the domain of f(x)=sqrt(2+x+x^2) ?
The domain of f(x)=sqrt(2+x+x^2) is -infinity <x<infinity