What is the range of (2x-2)/(x+2) ?

The range of (2x-2)/(x+2) is f(x) 2

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range of (2x-2)/(x+2)

range

\frac{2 x - 2}{x + 2}

f (x) < 2 or f (x) > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{2 x - 2}{x + 2}

Inverse of

\frac{2 x - 2}{x + 2} : \frac{- 2 - 2 x}{x - 2}

\frac{- 2 - 2 x}{x - 2}

Find the domain of each inverse function

Domain of

\frac{- 2 - 2 x}{x - 2} : x < 2 or x > 2

Combine the intervals

f (x) < 2 or f (x) > 2

y = \frac{1}{3} x

f (x) = x^{3} + 4 x^{2} - 4 x - 16

\frac{2}{5} x - 6

f (x) = 2 csc (\frac{x}{3})

What is the range of (2x-2)/(x+2) ?
The range of (2x-2)/(x+2) is f(x)<2\lor f(x)>2