What is the domain of (x^2+2x+1)/(2x^2-x-3) ?

The domain of (x^2+2x+1)/(2x^2-x-3) is x 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x^2+2x+1)/(2x^2-x-3)

domain

\frac{x ^{2} + 2 x + 1}{2 x ^{2} - x - 3}

x < - 1 or - 1 < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - 1) \cup (- 1, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}, x = - 1

The function domain

x < - 1 or - 1 < x < \frac{3}{2} or x > \frac{3}{2}

f (x) = \frac{3 x - 3}{x ^{2} - 1}

f (x) = x^{2} x^{2} - 9

f (x) = \frac{5 x}{3} + 5

f (x) = \frac{x ^{2} + 8 x + 15}{x + 3}

\frac{x ^{2} - 8 x}{x + 2}

What is the domain of (x^2+2x+1)/(2x^2-x-3) ?
The domain of (x^2+2x+1)/(2x^2-x-3) is x<-1\lor-1<x< 3/2 \lor x> 3/2