What is the inverse of f(x)=x^2-7,x>= 0 ?

The inverse of f(x)=x^2-7,x>= 0 is sqrt(x+7),-sqrt(x+7)

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inverse of f(x)=x^2-7,x>= 0

inverse

f (x) = x^{2} - 7, x \geq 0

x + 7, - x + 7

Solution steps

y = x^{2} - 7

Replace

x

with

y

x = y^{2} - 7

Solve for

y, x = y^{2} - 7

x + 7, - x + 7

f (x) = \frac{x - 2}{x}

f (x) = \frac{7 x}{x + 6}

f (x) = \frac{- 2}{- 2 x + 3}

f (x) = 4^{x + 1} - 2

sin (3 x)

What is the inverse of f(x)=x^2-7,x>= 0 ?
The inverse of f(x)=x^2-7,x>= 0 is sqrt(x+7),-sqrt(x+7)