What is the inverse of f(x)=(9-10x)^{5/2} ?

The inverse of f(x)=(9-10x)^{5/2} is -(x^{2/5}-9)/(10)

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inverse of f(x)=(9-10x)^{5/2}

inverse

f (x) = (9 - 10 x)^{\frac{5}{2}}

- \frac{x ^{\frac{2}{5}} - 9}{10}

Solution steps

y = (9 - 10 x)^{\frac{5}{2}}

Replace

x

with

y

x = (9 - 10 y)^{\frac{5}{2}}

Solve for

y, x = (9 - 10 y)^{\frac{5}{2}}

- \frac{x ^{\frac{2}{5}} - 9}{10}

f (x) = 3^{2 x - 1}

f (x) = 8 - \frac{3}{x ^{2}}

cos (x) - 3

y = - x + 7

f (x) = - x + 3

What is the inverse of f(x)=(9-10x)^{5/2} ?
The inverse of f(x)=(9-10x)^{5/2} is -(x^{2/5}-9)/(10)