What is the domain of f(x)=sqrt(6x+3) ?

The domain of f(x)=sqrt(6x+3) is x>=-1/2

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domain of f(x)=sqrt(6x+3)

domain

f (x) = 6 x + 3

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

The function domain

x \geq - \frac{1}{2}

f (x) = \frac{2 x + 6}{- x ^{2} - 5 x + 24}

y = \frac{1}{2} x - 1

9 x - 8

y = 5 x 2, (1, 1)

f (x) = - 6 x + 2

What is the domain of f(x)=sqrt(6x+3) ?
The domain of f(x)=sqrt(6x+3) is x>=-1/2