What is the inverse of f(x)=x^2+2x-3 ?

The inverse of f(x)=x^2+2x-3 is -1+sqrt(x+4),-sqrt(x+4)-1

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inverse of f(x)=x^2+2x-3

inverse

f (x) = x^{2} + 2 x - 3

- 1 + x + 4, - x + 4 - 1

Solution steps

y = x^{2} + 2 x - 3

Replace

x

with

y

x = y^{2} + 2 y - 3

Solve for

y, x = y^{2} + 2 y - 3

- 1 + x + 4, - x + 4 - 1

f (x) = [[5 x - 15]] + 40

f (x) = \frac{3}{10} x + \frac{3}{2}

f (x) = \frac{4 x}{x ^{3} - 4 x}

f (x) = \frac{- 2 x ^{3}}{( x - 3 )}

x - 3 y = - 3

What is the inverse of f(x)=x^2+2x-3 ?
The inverse of f(x)=x^2+2x-3 is -1+sqrt(x+4),-sqrt(x+4)-1