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Popular >

distance (3,-3),(1,5)

Solution

distance

(3, - 3), (1, 5)

Solution

217

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(3, - 3)

and

(1, 5)

is

= (1 - 3)^{2} + (5 - (- 3))^{2}

Simplify

= 217

Popular Examples

inflection x/(x^2+49)inflection points

\frac{x}{x ^{2} + 49}

inverse of f(x)=2x^2-8 inverse

f (x) = 2 x^{2} - 8

parallel y=-4x-1,(2,-4)parallel

y = - 4 x - 1, (2, - 4)

inverse of f(x)=(x+8)/(x+6)inverse

f (x) = \frac{x + 8}{x + 6}

asymptotes of f(x)=(6x)/(10x-7)asymptotes

f (x) = \frac{6 x}{10 x - 7}

Frequently Asked Questions (FAQ)

What is the distance (3,-3),(1,5) ?
The distance (3,-3),(1,5) is 2sqrt(17)