What is the inverse of f(x)=\sqrt[3]{x-4}+3 ?

The inverse of f(x)=\sqrt[3]{x-4}+3 is x^3-9x^2+27x-23

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inverse of f(x)=\sqrt[3]{x-4}+3

inverse

x^{3} - 9 x^{2} + 27 x - 23

Solution steps

Replace

x

with

y

Solve for

x^{3} - 9 x^{2} + 27 x - 23

\frac{1}{2} x - y = - 2, (2, 4)

f (x) = \frac{1}{- 10 x + 3}

f (x) = lo g_{5} (∣ x ∣)

\frac{3}{x - 1}

\frac{x ^{2} + 4}{x ^{2} - 4}

What is the inverse of f(x)=\sqrt[3]{x-4}+3 ?
The inverse of f(x)=\sqrt[3]{x-4}+3 is x^3-9x^2+27x-23