What is the perpendicular y=-1,(8,-4) ?

The perpendicular y=-1,(8,-4) is x=8

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perpendicular y=-1,(8,-4)

perpendicular

y = - 1, (8, - 4)

x = 8

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 1

that passes through

(8, - 4)

Find the slope of

y = - 1 : m = 0

Compute the slope of the perpendicular line:

m_{p} = \infty

Find the line with slope m=

\infty

and passing through

(8, - 4) : x = 8

x = 8

f (x) = \frac{1}{16} (x - 1)^{2} - 4

f (x) = \frac{1 - e ^{x}}{1 + e ^{x}}

f (x) = \frac{13}{x - 7}

f (x) = 12 - x^{2}

2 x^{3} - 6 x^{2} + 4