What is the perpendicular y= 3/2 x-1,(2,3) ?

The perpendicular y= 3/2 x-1,(2,3) is y=-2/3 x+13/3

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perpendicular y= 3/2 x-1,(2,3)

perpendicular

y = \frac{3}{2} x - 1, (2, 3)

y = - \frac{2}{3} x + \frac{13}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{2} x - 1

that passes through

(2, 3)

Find the slope of

y = \frac{3}{2} x - 1 : m = \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(2, 3) : y = - \frac{2}{3} x + \frac{13}{3}

y = - \frac{2}{3} x + \frac{13}{3}

y = 4 x - 8

f (x) = - \frac{3}{4} x + 12

y = - \frac{7}{2} x - 10, at 7 x - 2 y - 2 = 0

f (x) = 8 - x^{2}

\frac{4}{\frac{4}{x}}

What is the perpendicular y= 3/2 x-1,(2,3) ?
The perpendicular y= 3/2 x-1,(2,3) is y=-2/3 x+13/3