en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2ln(x-1)+5

Solution

inverse

f (x) = 2 ln (x - 1) + 5

Solution

e^{\frac{x - 5}{2}} + 1

Solution steps

y = 2 ln (x - 1) + 5

Replace

x

with

y

x = 2 ln (y - 1) + 5

Solve for

y, x = 2 ln (y - 1) + 5

e^{\frac{x - 5}{2}} + 1

Popular Examples

critical f(x)=-2x+7 critical points

f (x) = - 2 x + 7

periodicity of y=6cos(2pix)periodicity

y = 6 cos (2 π x)

domain of f(x)=((6x+36))/x domain

f (x) = \frac{( 6 x + 36 )}{x}

asymptotes of sqrt(x^2+2x+15)asymptotes

x^{2} + 2 x + 15

critical f(x)=x+4/(x^2)critical points

f (x) = x + \frac{4}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the inverse of f(x)=2ln(x-1)+5 ?
The inverse of f(x)=2ln(x-1)+5 is e^{(x-5)/2}+1