What is the range of (x^2-25)/(x+5) ?

The range of (x^2-25)/(x+5) is f(x) -10

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range of (x^2-25)/(x+5)

range

\frac{x ^{2} - 25}{x + 5}

f (x) < - 10 or f (x) > - 10

Interval Notation

(- \infty, - 10) \cup (- 10, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x ^{2} - 25}{x + 5} : x < - 5 or x > - 5

Simplify

\frac{x ^{2} - 25}{x + 5} : x - 5

Extreme Points of

x - 5 :

None

Find the range for the interval

- \infty < x < - 5 : - \infty < f (x) < - 10

Find the range for the interval

- 5 < x < \infty : - 10 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) < - 10 or f (x) > - 10

f (x) < - 10 or f (x) > - 10

y = 2 x + 5

f (x) = \frac{x + 1}{x ^{2} + 3}

- 2 x - 4

f (x) = \frac{x + 3}{x + 10}

f (x) = 3 x + 3

What is the range of (x^2-25)/(x+5) ?
The range of (x^2-25)/(x+5) is f(x)<-10\lor f(x)>-10