What is the domain of f(x)=(\sqrt[4]{x})^5 ?

The domain of f(x)=(\sqrt[4]{x})^5 is x>= 0

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domain of f(x)=(\sqrt[4]{x})^5

domain

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

x^{4} - 9 x^{2}

f (x) = 9 x - 4

3 x

f (x) = \frac{6}{5} x^{2} + \frac{3}{2}

(11.2, - 2.2), (5.2, - 10.2)

What is the domain of f(x)=(\sqrt[4]{x})^5 ?
The domain of f(x)=(\sqrt[4]{x})^5 is x>= 0