What is the domain of f(x)=sqrt(3x+15) ?

The domain of f(x)=sqrt(3x+15) is x>=-5

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domain of f(x)=sqrt(3x+15)

domain

f (x) = 3 x + 15

x \geq - 5

Interval Notation

[- 5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 5

The function domain

x \geq - 5

3 x^{2} + x - \frac{1}{12} = 0

f (x) = 6 x^{2} + 2 x^{3}

(0.3, 0.7), (0.1, 0.9)

f (x) = \frac{2 x + 4}{x ^{2} - 5 x}

f (x) = 4 - 5 x + x^{2}

What is the domain of f(x)=sqrt(3x+15) ?
The domain of f(x)=sqrt(3x+15) is x>=-5