What is the domain of f(x)=(2x+4)/(x^2-5x) ?

The domain of f(x)=(2x+4)/(x^2-5x) is x 5

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domain of f(x)=(2x+4)/(x^2-5x)

domain

f (x) = \frac{2 x + 4}{x ^{2} - 5 x}

x < 0 or 0 < x < 5 or x > 5

Interval Notation

(- \infty, 0) \cup (0, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = 0

The function domain

x < 0 or 0 < x < 5 or x > 5

f (x) = 4 - 5 x + x^{2}

\frac{1}{x} - 4

\frac{x ^{2} - x}{x ^{2} - 5 x + 4}

f (x) = \frac{x}{x ^{2} + 7 x + 6}

f (x) = 4 x - 3

What is the domain of f(x)=(2x+4)/(x^2-5x) ?
The domain of f(x)=(2x+4)/(x^2-5x) is x<0\lor 0<x<5\lor x>5